背景

早上看了，觉得有趣，实现一个Windows Mobile版本。很多年前我也有一台文曲星，也常常玩这个猜数字游戏，所以尝试在Windows Mobile下实现。

方案

强调需要TDD，所以我的实现方案也是TDD。

实现

使用NUintLite

测试代码需要使用NUintLite，NUintLite具体可以参考 。修改Main函数如下，把结果写到SD卡上。

static void Main(string[] args)         {
              System.IO.TextWriter writer = new System.IO.StreamWriter("\\Storage Card\\TestResult.txt"); new NUnitLite.Runner.TextUI(writer).Execute(args);             writer.Close(); Application.Run(new MainForm());         }

编写测试代码

TDD，先写测试代码。测试代码的逻辑是按照写的，在实际使用中根据功能需求编写。

[TestFixture] class BingleTest {
  private Bingle bingle;         [SetUp] public void SetUp()         {
              bingle = new Bingle();         }         [TearDown] public void TearDown()         {
          }         [Test] public void BuildAnswersTest()         {
              bingle.BuildAnswers(); Assert.True(bingle.Answers[0] != bingle.Answers[1]                     && bingle.Answers[0] != bingle.Answers[2]                     && bingle.Answers[0] != bingle.Answers[3]                     && bingle.Answers[1] != bingle.Answers[2]                     && bingle.Answers[1] != bingle.Answers[3]                     && bingle.Answers[2] != bingle.Answers[3]);         }         [Test] public void MatchTest()         {
              bingle.Answers = new int[] { 1, 2, 3, 4 }; int a; int b; int[] num; //1 5 6 7      1A0B num = new int[] { 1, 5, 6, 7 };             bingle.Match(num, out a, out b); Assert.That(a, Is.EqualTo(1)); Assert.That(b, Is.EqualTo(0)); //2 4 7 8      0A2B num = new int[] { 2, 4, 7, 8 };             bingle.Match(num, out a, out b); Assert.That(a, Is.EqualTo(0)); Assert.That(b, Is.EqualTo(2)); //0 3 2 4      1A2B num = new int[] { 0, 3, 2, 4 };             bingle.Match(num, out a, out b); Assert.That(a, Is.EqualTo(1)); Assert.That(b, Is.EqualTo(2)); //5 6 7 8      0A0B num = new int[] { 5, 6, 7, 8 };             bingle.Match(num, out a, out b); Assert.That(a, Is.EqualTo(0)); Assert.That(b, Is.EqualTo(0)); //4 3 2 1      0A4B num = new int[] { 4, 3, 2, 1 };             bingle.Match(num, out a, out b); Assert.That(a, Is.EqualTo(0)); Assert.That(b, Is.EqualTo(4)); //1 2 3 4      4A0B num = new int[] { 1, 2, 3, 4 };             bingle.Match(num, out a, out b); Assert.That(a, Is.EqualTo(4)); Assert.That(b, Is.EqualTo(0));         }         [Test]         [ExpectedException(typeof(ArgumentException))] public void MatchTest2()         {
  int a; int b; int[] num; //1 1 2 3 num = new int[] { 1, 1, 2, 3 };             bingle.Match(num, out a, out b); //1 2 num = new int[] { 1, 2 };             bingle.Match(num, out a, out b);         }     }

 我把对Match测试的代码写在一起，我喜欢一个Test函数对应一个功能函数。而把异常处理分开出来写了，怕前面的测试抛出异常，导致测试通过了。

功能代码

功能代码的目的就是通过所以单元测试。

public class Bingle {
  public int[] Answers { set; get; } private int attemptTimes; public int AttemptTimes         {
  get {
  return attemptTimes;             }         } public Bingle()         {
              Answers = new int[4];         } public void BuildAnswers()         {
  Random r = new Random(); while(true)             {
  int i = r.Next(9999);                 Answers[0] = i / 1000;                 Answers[1] = i % 1000 / 100;                 Answers[2] = i % 100 / 10;                 Answers[3] = i % 10; if (Answers[0] != Answers[1]                     && Answers[0] != Answers[2]                     && Answers[0] != Answers[3]                     && Answers[1] != Answers[2]                     && Answers[1] != Answers[3]                     && Answers[2] != Answers[3])                 {
  return;                 }             }         } public bool Match(int[] attemptNum, out int bingle, out int match)         {
              bingle = 0;             match = 0; if (attemptNum.Length != 4)             {
  throw new ArgumentException("Should be 4 digits.");             } if(!(attemptNum[0] != attemptNum[1]                     && attemptNum[0] != attemptNum[2]                     && attemptNum[0] != attemptNum[3]                     && attemptNum[1] != attemptNum[2]                     && attemptNum[1] != attemptNum[3]                     && attemptNum[2] != attemptNum[3]))             {
  throw new ArgumentException("Should be non repeating 4 digits.");             }             ++attemptTimes; for(int i=0; i<4; ++i)             {
  if (attemptNum[i] == Answers[i])                 {
                      ++bingle;                 } else {
  for (int j = 0; j < 4; ++j)                     {
  if (attemptNum[i] == Answers[j])                         {
                              ++match;                         }                     }                 }             } return (bingle == 4);         }     }

单元测试结果

如果通过所有单元测试，说明功能代码编写完毕，每次修改都有run单元测试。

NUnitLite version 0.2.0 Copyright 2007, Charlie Poole Runtime Environment -     OS Version: Microsoft Windows CE 5.2.21234   .NET Version: 2.0.7045.0 3 Tests : 0 Errors, 0 Failures, 0 Not Run

 

UI 处理

功能代码写完以后，可以写UI了，具体UI代码见源代码，下面是执行效果。

 

源代码：

环境： VS 2008 + WM 6 professional SDK + NUnitLite